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Question

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by the equation, U=7x+24y Joule. Here x and y are in the meter at t=0, the particle is at the origin and moving with velocity (2^i+3^j)m/s. The magnitude of acceleration of particle is

A
3 m/s2
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B
5 m/s2
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C
31 m/s2
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D
15 m/s2
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Solution

The correct option is D 5 m/s2
Given,

m=5kg

u=7x+24y

v=2^i+3^j

Fx=dudx=7

Fy=dudy=24

|F|=49+576=25

a=Fm=255=5m/s2

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