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# The potential energy of a particle of mass 5 kg moving in xy-plane is given as U = (7x + 24y) joule, x and y being in metre. Initially at t = 0, the particle is at the origin (0, 0) moving with a velocity of (8.6^i+23.2^j)ms−1. Then

A
The velocity of the particle at t =4 s, is 5ms1
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B
The acceleration of the particle is 5ms2
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C
The direction of motion of the particle initially (at t = 0) is at right angles to the direction of acceleration
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D
The path of the particle is circle
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Solution

## The correct option is B The acceleration of the particle is 5ms−2fx=−dvdx=−7Nfy=−dv∂y=−24NF=√f2x+f2y=25NAcceleration =Fm=255=5m/s2

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