The potential energy of a particle of mass m is given by V(x)={E000≤x≤1x>1} λ1 and λ2 are the de-Broglie wavelengths of the particle, when 0≤x≤1 and x>1 respectively. If the total energy of particle is 2E0, find (λ1/λ2).
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Solution
Total energy , E=T+V where T=Kinetic energy and V=potential energy.