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Question

The potential energy of a particle of mass m is given by
U(x)={E0;0x10;x>1
λ1 and λ2 are the de-Broglie wavelengths of the particle, when 0x1 and x>1 respectively. If the total energy of particle is 3E0, the ratio λ1λ2 will be

A
2
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B
1
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C
2
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D
32
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Solution

The correct option is D 32
K.E=3E0E0=2E0(for0x1)λ1=h2m2E0
K.E.=3E0(forx>1)λ2=h2m3E0λ1λ2=32

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