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Question

The potential energy of a particle varies with distance x as U=Ax1/2x2+B, where A and B are constants. The dimensional formula for A x B is:

A
M1L7/2T2
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B
M1L11/4T2
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C
M1L5/2T2
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D
M1L9/2T2
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Solution

The correct option is B M1L11/4T2
Given, U=Ax1/2x2+B
x2+B should have some dimension L2=dim(B)
dim(A)=dim(U×(x2+B)x1/2)=[ML2T2][L2]L1/2
=ML7/2T2
dim(A×B)=[ML7/2T2][L2]=[ML11/2T2]

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