Question

The potential energy of an electron in 3rd Bohr orbit of H atom is

Answer 1

Using the formula E=−13.6z2/n2eV
E=−13.6 *z2/n2 eV Where z is atomic no. And n is the no of orbit
So energy of third orbit of he would be
−13.6×(1*1/3*3)
=−1.51 eV)