The potential energy of an electron in the fifth orbit of hydrogen atom is

0.54 e V

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- 0.54 e V

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1.08 e V

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- 1.08 e V

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Solution

The correct option is D $- 1.08 e V$
Potential energy: It is two times total energy.
Therefore, $P . E = - 27.2 \times \frac{1}{25} = - 1.088 e V$

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The potential energy of an electron in the fifth orbit of hydrogen atom is

The correct option is D −1.08 eVPotential energy: It is two times total energy.Therefore, P.E=−27.2×125 =−1.088 eV

The correct option is D $- 1.08 e V$
Potential energy: It is two times total energy.
Therefore, $P . E = - 27.2 \times \frac{1}{25} = - 1.088 e V$