Question

The potential energy of particle of mass 'm' is given by $U=\frac{1}{2}k{x}^2$ for x<0 and U = 0 for x $\ge$ 0. If total mechanical energy of the particle is E. Then its speed at $x=\sqrt{\frac{2E}{k}}$ is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Potential energy of particle at $x=\sqrt{\frac{2E}{k}}$ is zero $\therefore$ K.E = E
$\Rightarrow \frac{1}{2}m{v}^2=Eorv=\sqrt{\frac{2E}{m}}$