The potential energy of particle of mass m varies as U(x)={E0:0≤x≤10:x>1The de Broglie wavelength of the particle in the range 0≤x≤1isλ1 and that in the range x>1isλ2. If the total energy of the particle is 2E0, find λ1,/λ2.
A
√2
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B
2
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C
1
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D
2√2
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Solution
The correct option is A√2
de Broglie wavelength of a particle of ///
λ=h√2mK
where K is the kinetic energy of the particle.
For 0≤x≤1,U(x)=E0
As, total energy = Kinetic energy + potential energy