The potential function of an electric field is given by $V = 2 x^{2} .$ Determine strength of the electrostatic field at the point $(2 m, 0, 3 m) .$

\to E = 4^i (N C^{- 1})

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\to E = - 4^i (N C^{- 1})

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\to E = 8^i (N C^{- 1})

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\to E = - 8^i (N C^{- 1})

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Solution

The correct option is D $\to E = - 8^i (N C^{- 1})$
$\to E = - \frac{δ V}{δ r}$
$\to E = - \frac{δ V_{x}}{δ x} - \frac{δ V_{y}}{δ y} - \frac{δ V_{z}}{δ z}$
$⟹ \to E = - \frac{δ (2 x^{2})}{δ x}$
$⟹ \to E = - 4 x$
At point (2, 0, 3) electric field will be
$\to E = - 8$ $N C^{- 1}$

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