Question

The power consumed by 6$\Omega$ resister in the given circuit of fig

• A. 4.611 W
• B. 3.375 w
• C. 1.125 w
• D. none of these

Answer 1

The correct option is B 3.375 w

Equivalent resistance A and B $R_{AB}=8\parallel 8=\frac{8\times 8}{8+8}=4\Omega$

Thus it is a balanced wheat stone bridge satisfying the condition, $\frac{2}{3}=\frac{4}{6}$

Hence no current flows through $10\Omega$ resistor, and thus equivalent circuit is shown above.

Current through $6\Omega$ resistor, $I=\frac{V}{3+6}=\frac{9}{9}=1$ A
Thus power consumed by $6\Omega$ resistor $P=I^{\prime 2}\left(6\right)=(\frac{3}{4}{)}^2\times 6=3.375$ W