The power of a water pump is $2 k W$ . If $g = 10 m s^{- 2}$ , the amount of water it can raise in one minute to a height of $10 m$ is:

2000 l i t r e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1000 l i t r e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 l i t r e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1200 l i t r e

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1200 l i t r e$
Given data,
$p$ is given as $2 k W$ $= 2000 w a t t$
$g = 10 m / s$
$h = 10 m$
we know that,
$P = \frac{m g h}{t}$
putting these values,
$2000 = \frac{(m \times 10 \times 10)}{60}$
$m = 1200 k g$
Therefore , the pump lifts $1200 k g$ or $1200 l$ of water to a height of $10 m$ every minute.

Suggest Corrections

Similar questions

2 k W

10 m

g = 10 m / s^{2}

2 k W

10 m

(g = 10 m / s^{2})

Power of a water pump is 2 kW. If $g = 10 m / s e c^{2}$ , the amount of water it can raise in one minute to a height of 10 m is

g = 10 m s^{- 2}

Join BYJU'S Learning Program