Question

The power output of an automobile engine is advertised to be $200$ hp at $600$ rpm. Find the corresponding torque.

• A. 137Nm
• B. 237Nm
• C. 337Nm
• D. 287Nm

Answer 1

The correct option is B 237Nm

Power is equal to the product of torque $\tau$ and the angular velocity $\omega$.
Thus we get
$\tau =\frac{P}{\omega }=\frac{200\times 746}{600\times \frac{2\pi }{60}}$
$=237Nm$