The premodal class and postmodal class rectangles have same height. If the modal class is $40 - 60$ , then what is mode ?

40

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60

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100

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50

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Solution

The correct option is B $50$
Let $f$ be the frequency of the modal class.
Let frequency of premodal class
$=$ frequency of postmodal class $= x$
Given, modal class $= 40 - 60$
$∴$ l $=$ lower limit $= 40$
$h = w i d t h = 60 - 40 = 20$
Now,
mode $= 40 +$ $\frac{f - x}{2 f - x - x} \times 20 = 40 + \frac{f - x}{2 f - 2 x} \times 20$
$= 40 + 10 = 50$
Hence, option 'D' is correct.

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