The correct option is D Glucose
A reducing sugar is the one that has a free aldehyde or a free ketone group. When reducing sugars are heated in a basic solution of Benedict's reagent containing copper sulfate enediols are formed. Endioles react with cupric ions in Benedict’s solution and reduce it to cuprous ions. Glucose being a reducing sugar gives a positive result for this test. As Benedict's solution is heated with glucose the color changes from green to yellow to orange. Finally, red color is obtained. Thus the correct answer is option B.