Question

The present age of a man is 3 years more than 3 times the age of his son. 3 years hence , the man's age will be 10 years more than twice the age of his son. Determine their present ages.

Answer 1

Present

Let the son's age be x.

Then, according to the condition given, father's age = 3x + 3

3 years later

Son's age= x + 3

Father's age = 3x + 3 + 3 = 3x + 6

According to the condition given,

3x + 6 = 10 + 2 ( x + 3 )

3x + 6 = 10 + 2x + 6

x = 10

Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.