The present age of a man is 3 years more than 3 times the age of his son. 3 years hence , the man's age will be 10 years more than twice the age of his son. Determine their present ages.
Present
Let the son's age be x.
Then, according to the condition given, father's age = 3x + 3
3 years later
Son's age= x + 3
Father's age = 3x + 3 + 3 = 3x + 6
According to the condition given,
3x + 6 = 10 + 2 ( x + 3 )
3x + 6 = 10 + 2x + 6
x = 10
Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.