Question

The present population of a village is 60,500 and it increases at the rate 10% per annum. What was the population 2 years ago?

• A. 55,000
• B. 60,000
• C. 50,000
• D. 52,000

Answer 1

Answer: (C)

50,000

Here, $A=60,500,R=10,N=2$.
Population N years ago $=\frac{A}{[1+(R/100){]}^N}=\frac{60,500}{[1-(10/100){]}^2}=\frac{60,500\times 100}{121}=50,000$