Question

The pressure and temperature of $4d{m}^3$ of carbon dioxide gas are doubled. Then volume of carbon dioxide would be :

• A. $2d{m}^3$
• B. $3d{m}^3$
• C. $4d{m}^3$
• D. $8d{m}^3$

Answer 1

The correct option is C $4d{m}^3$

The combined gas law or general gas equation is obtained by combining Boyle's Law, Charles' Law, and Gay-Lussac's Law. It shows the relationship between the pressure, volume, and temperature for a fixed mass (quantity) of gas.

$\because \frac{p_1{V}_1}{T_1}=\frac{p_1{V}_2}{T_2}$

$\frac{p_1\times 4}{T_1}=\frac{2p_1\times V_2}{2T_1}$

$2V_2=8$

$V_2=4d{m}^3$

Option C is correct.