Question

The pressure and temperature of $4d{m}^3$ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be :

• A. $2d{m}^3$
• B. $3d{m}^3$
• C. $4d{m}^3$
• D. $8d{m}^3$

Answer 1

Answer: (C)

$4d{m}^3$

Assume ideal gas behaviour,

$PV=nRT$

$P_1{V}_1/T_1=P_2{V}_2/T_2$

According to question,

$P_2=2P_1,T_2=2T_1$

So, $\frac{P_1{V}_1}{T_1}=\frac{2P_1{V}_2}{2\times T_1}$

=> $V_1=V_2$, So volume remains constant

Option C is correct.