Question

The pressure at a depth of 200 m below the surface of the sea, will be ___KPa.

The density of seawater is 1024 kg/m³.

Answer 1

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by dgh.
The given values are: d = 1024 $\frac{kg}{m^3}$, h = 200 m and g = 10 $\frac{m}{{sec}^2}$.
Thus, pressure = dgh = 1024 $\times$ 200 $\times$ 10 = 2048,000 Pa = 2048 KPa .