CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Dalton's Law of Partial Pressures

The pressure ...

Question

The pressure of $1 g$ of an ideal gas $A$ at $300 K$ is found to be 2 bar. When $2 g$ of another ideal gas $B$ is introduced in the same flask at the same temperature, the pressure becomes 3 bar. Which of the following is correct?
( $m_{A}$ = mass of gas A; $m_{B}$ = mass of gas B)

A

m_{B} = 4 m_{A}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

m_{A} = 3 m_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

m_{B} = 3 m_{A}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

m_{A} = m_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $m_{B} = 4 m_{A}$
Given,
Mass of gas A, $w_{A} = 1 g$
Mass of gas B, $w_{B} = 2 g$
$p_{A} = 2 bar$
$P_{t o t a l} = 3 bar$
$P_{t o t a l} = p_{A} + p_{B}$
$p_{B} = 3 - 2 = 1 bar$
$P V = n R T \Rightarrow P V = \frac{W}{M} R T$
$\frac{p_{A} m_{A}}{w_{A}} = \frac{p_{B} m_{B}}{w_{B}} or \frac{2 \times m_{A}}{1} = \frac{1 \times m_{B}}{2} or \frac{m_{A}}{m_{B}} = \frac{1}{4} or m_{B} = 4 m_{A}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The pressure of

1 g

of an ideal gas

A

300 K

2 b a r

2 g

of another ideal gas

B

is introduced in the same flask at the same temperature, the pressure becomes

3 b a r

. Which of the following is correct?
(

m_{A} =

A

m_{B}

B

)

Q. The pressure of

1 g

of an ideal gas

A

300 K

is found to be 2 bar. When

2 g

of another ideal gas

B

is introduced in the same flask at the same temperature, the pressure becomes 3 bar. Which of the following is correct?

(m_{A}

= mass of gas A;

m_{B}

)

Q. Pressure of 1 g of an ideal gas A at 27

^{\circ} C

is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses?

1 g

of an ideal gas

A

27^{\circ} C

is found to be 2 bar. When

2 g

of another ideal gas

B

is introduced in the same flask at the same temperature, the pressure becomes 3 bar. Find a relationship between their molecular masses.

1 g

of an ideal gas

A

27^{\circ} C

2 b a r

2 g

of another ideal gas

B

is introduced in the same flask at same temperature the pressure becomes

3 b a r

. What would be the ratio of their molecular masses?

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Dalton's Law of Partial Pressures

Standard XIII Chemistry

Join BYJU'S Learning Program

CrossIcon