Question

The pressure of $2L$ of $O_2$ gas is doubled when its temperature is increased from 300 K to 600 K. Find the final volume of the gas.

• A. 4 L
• B. 40 L
• C. 20 L
• D. 2 L

Answer 1

The correct option is D 2 L

Initial conditions:
$T_1$ = 300 K
$V_1$ = 2L
Let the initial pressure be $P_1$.

Final conditions:
$T_2$ = 600 K
$V_2=?$
$P_2$ = 2 $P_1$

Using combined gas law equation,
$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$
$\frac{P_1\times 2}{300}=\frac{2P_1\times V_2}{600}$
$V_2=2L$