The pressure of $2$ moles of ideal gas at $546 K$ having volume $44.8$ litres is:

2 a t m

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3 a t m

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4 a t m

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1.5 a t m

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Solution

The correct option is A $2 a t m$
$P = \frac{n R T}{V}$
$P = \frac{2 \times 0.082 \times 546}{44.8}$
Thus, $P = 2 a t m$

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