The pressure of air increases by 100 mm to Hg the temperature decreases by 1-c-what will be the change in the speed of sound in air-

The correct option is C 61 cms^ 1 V_t=331.3+0.606 × t m/sec, V_(t+1)=331.3+ 0.606 × (t+1) m/sec, Δ V=V_(t+1) V_t=0.606 m, Δ V=60.6 cms ...

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Byju's Answer

Standard IX

Physics

Speed of Sound

The pressure ...

Question

The pressure of air increases by 100 mm to Hg the temperature decreases by $1^{\circ} c$ .what will be the change in the speed of sound in air?

61 m s^{- 1}

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61 m m^{- 1}

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61 c m s^{- 1}

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none of the above

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Solution

The correct option is C $61 c m s^{- 1}$
$V_{t} = 331.3 + 0.606 \times t$ m/sec,
$V_{(t + 1)} = 331.3 + 0.606 \times (t + 1)$ m/sec,
$Δ V = V_{(t + 1)} - V_{t} = 0.606$ m\sec,
$Δ V = 60.6 c m s^{- 1}$
pressure does not make any change on the velocity of sound in gases.
Option 'C' is correct.

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The pressure of air increases by 100 mm to Hg the temperature decreases by 1∘c.what will be the change in the speed of sound in air?

The correct option is C 61cms−1Vt=331.3+0.606×t m/sec,V(t+1)=331.3+0.606×(t+1) m/sec,ΔV=V(t+1)−Vt=0.606 m\sec,ΔV=60.6cms−1pressure does not make any change on the velocity of sound in gases.Option 'C' is correct.

The pressure of air increases by 100 mm to Hg the temperature decreases by $1^{\circ} c$ .what will be the change in the speed of sound in air?

The correct option is C $61 c m s^{- 1}$
$V_{t} = 331.3 + 0.606 \times t$ m/sec,
$V_{(t + 1)} = 331.3 + 0.606 \times (t + 1)$ m/sec,
$Δ V = V_{(t + 1)} - V_{t} = 0.606$ m\sec,
$Δ V = 60.6 c m s^{- 1}$
pressure does not make any change on the velocity of sound in gases.
Option 'C' is correct.