You visited us 1 times! Enjoying our articles? Unlock Full Access!

EMF

The pressure ...

Question

The pressure of hydrogen gas is increased from $1 a t m$ to $100 a t m$ . Keeping the $H^{+} (1 M)$ constant, the voltage of the hydrogen half-cell at $25^{\circ} C$ will be_____________.

0.059 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.59 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0295 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.118 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.059 V$
We have,
$2 H^{+} + 2 e^{-} \to H_{2}$
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{2} l o g \frac{1}{(P_{H_{2}})}$
$E_{c e l l} = 0 + \frac{0.0591}{2} l o g (100)$
$E_{c e l l} = 0.0591 V$

Suggest Corrections

Similar questions

H_{2}

1

100

H^{+}

1 M

25^{o} C

1

100

1

25^{o}

(P_{H_{2}} = 1 a t m s : [H^{'}] = 0.1 M]

25^{\circ} C

27^{\circ} C

227^{\circ} C

1

25^{o} C

P t ∣ ∣ H_{2 (g)} ∣ ∣ H C l (a q)

p H = 3

H_{2}

Join BYJU'S Learning Program