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Question

The price of a book is 4 rupees more than the price of a pen; and the price of a pencil is 2 rupees less than the price of this pen. A man bought 5 books, 2 pens and 3 pencils and paid 54 rupees for the lot. What is the price of each?

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Solution

Let the price of the pen be Rs.x

The price of the book = Rs (x + 4)

The price of the pencil = Rs (x − 2)

Cost of 5 books = Rs 5(x + 4) = Rs (5x + 20)

Cost of 2 pens = Rs.2x

Cost of 3 pencils = Rs 3(x − 2) = Rs (3x − 6)

Total amount paid = Rs.54

Algebraic form of the problem is:

5x + 20 + 2x + 3x − 6 = 54

10x + 14 = 54

10x = 54 − 14

10x = 40

Cost of one pen = Rs.4

Cost of one book = Rs (4 + 4) = Rs.8

Cost of one pencil = Rs (4 − 2) = Rs.2


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