The primary coil of a transformer has 132, 000 turns and is connected to A.C input source of 220 V. The secondary coil has 2,400 turns. Find the output voltage.

4.0 V

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4.5 V

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6.0 V

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5.5 V

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Solution

The correct option is A 4.0 V
Given,
$N_{p} = 132, 000, N_{s} = 2, 400, E_{p} = 220 V, E_{s} = ?$
We know, $\frac{E_{s}}{E_{p}} = \frac{N_{s}}{N_{p}}$
$E_{s} = \frac{2, 400}{132, 000} \Rightarrow \frac{2, 400}{132, 000} \times 220 = \frac{2400}{600} = 4 V$

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The primary coil of a transformer has 132, 000 turns and is connected to A.C input source of 220 V. The secondary coil has 2,400 turns. Find the output voltage.

The correct option is A 4.0 VGiven, Np=132,000,Ns=2,400,Ep=220 V,Es=? We know, EsEp=NsNp Es = 2,400132,000⇒2,400132,000×220=2400600=4 V

The correct option is A 4.0 V
Given,
$N_{p} = 132, 000, N_{s} = 2, 400, E_{p} = 220 V, E_{s} = ?$
We know, $\frac{E_{s}}{E_{p}} = \frac{N_{s}}{N_{p}}$
$E_{s} = \frac{2, 400}{132, 000} \Rightarrow \frac{2, 400}{132, 000} \times 220 = \frac{2400}{600} = 4 V$