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Question

The principal organic product formed in the reaction is:
CH2=CH(CH2)8COOH+HBrPeroxide−−−−

A
CH3CH(Br)(CH2)8COOH
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B
CH2=CH(CH2)8COBr
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C
BrCH2(CH2)9COOH
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D
CH2=CH(CH2)7CH(Br)COOH
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Solution

The correct option is C BrCH2(CH2)9COOH
CH2=CH(CH2)8COOH+HBrPeroxide−−−− BrCH2(CH2)9COOH.
A molecule of HBr is added to C=C double bond. Br is added to less substituted terminal carbon atom. (The anti markonikov's addition of HBr to unsymmetrical alkenes in presence of peroxides)

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