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Question

The principle organic product formed in the reaction given below:
CH2=CH(CH2)8COOH+HBrperoxide

A
CH3=CHBr(CH2)8COOH
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B
CH2=CH(CH2)8COBr
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C
CH2=BrCH2(CH2)8COOH
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D
CH2=CH(CH2)7COBrCOOH
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Solution

The correct option is C CH2=BrCH2(CH2)8COOH
The product forms in aledane with anti markonikov rule due to presence of peuride halogen attaches to less substituted carbon atom.
1174128_989572_ans_569f13c7149343dfa2d6557c971c0c94.PNG

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