The principal value of arg z where z=1+cos6π5+isin6π5 is given by
A
3π5
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B
−π5
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C
−3π5
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D
π5
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Solution
The correct option is A3π5 1+cos6π5+isin(6π5) =2cos23π5+i2sin3π5.cos3π5 =2cos(3π5)[cos3π5+isin3π5] =2cos(3π5)[cos3π5+isin3π5] ....Since 3π5 is in the first quadrant.