Question

The probability of getting 53 Fridays in a leap year is .

• A. $\frac{2}{7}$
• B. $\frac{1}{7}$
• C. $\frac{4}{7}$
• D. $\frac{3}{7}$

Answer 1

The correct option is A $\frac{2}{7}$

A Leap year has 366 days = (52 $\times$ 7 + 2) days = 52 weeks and 2 days

Thus a leap year always has 52 Fridays.

The remaining two days can be:

(i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday

(iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday

(vii) Saturday and Sunday

Since, Friday occurs in two cases:

P(53 Fridays in a leap year) = $\frac{2}{7}$