The probability of getting an even number, when a die is thrown once is :

\frac{1}{2}

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\frac{1}{3}

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\frac{1}{6}

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\frac{5}{6}

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Solution

The correct option is A $\frac{1}{2}$
Total space = 6
Favorable outcome = 2,4,6
$P = \frac{3}{6} = \frac{1}{2}$

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A die is thrown once. The probability of getting an even number is
(a) $\frac{1}{2}$ (b) $\frac{1}{3}$ (c) $\frac{1}{6}$ (d) $\frac{5}{6}$

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