The probability of getting at least one tail in $4$ throws of a coin is -

\frac{1}{16}

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\frac{1}{4}

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\frac{15}{16}

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\frac{1}{8}

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Solution

The correct option is C $\frac{15}{16}$
Required probability $= 1 - (\frac{1}{2})^{4} = \frac{15}{16}$

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