The probability of throwing a number greater than 2 with a fair dice is

(a) $\frac{3}{5}$

(b) $\frac{2}{5}$

(c) $\frac{2}{3}$

(d) $\frac{1}{3}$

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Solution

GIVEN: A dice is thrown once

TO FIND: Probability of getting a number greater than 2.

Total number on a dice is 6.

Number greater than 2 is 3, 4, 5 and 6

Total number greater than 2 is 4

We know that PROBABILITY =

Hence probability of getting a number greater than 2 is equal to

Hence the correct option is

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Similar questions

\frac{2}{5}

\frac{5}{6}

\frac{1}{3}

\frac{2}{3}

2

The probability of throwing a number greater than 2 with a fair die is
(a) $\frac{2}{5}$ (b) $\frac{5}{6}$ (c) $\frac{1}{3}$ (d) $\frac{2}{3}$

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