Question

The probability of winning free passes to a concert is $\frac{1}{20}.$ What are the odds in favor and the odds against it?

• A. $1:19$ and $19:1$
• B. $19:1$ and $1:19$
• C. $1:20$ and $20:1$
• D. $20:1$ and $1:20$

Answer 1

The correct option is A $1:19$ and $19:1$

Given,
$P\left(\text{winning}\right)=\frac{1}{20}$
That means $1$ out of the $20$ player will win the concert. So number of losers is $19$
$\therefore$ Number of favorable outcome $=1$ and Number of unfavorable outcome $=19$

Odds in favor of winning a free pass $=\frac{\text{Number of favorable outcome}}{\text{Number of unfavorable outcome}}=1:19$

Odds against winning a free pass$=\frac{\text{Number of unfavorable outcome}}{\text{Number of favorable outcome}}=19:1$