The probability that a marksman will hit a target is given as 1/5. Then his probability at least one hit in 10 shots is.
A
1−(45)10
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
15
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1−15,
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A1−(45)10 Here given n=10,p=15 Event of hitting the target is independent to each other. Hence required probability is =1−P(X=0)=1−10C0(45)10=1−(45)10