The probability that bulbs selected randomly from the lot has life less than 900 hours is :

\frac{11}{40}

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\frac{5}{16}

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\frac{7}{16}

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\frac{9}{16}

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Solution

The correct option is D $\frac{9}{16}$
$t o t a l f a v o u r a b l e c a s e s = 10 + 12 + 23 = 45 ∴ P (e v e n t) = \frac{45}{80} = \frac{9}{16}$

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Similar questions

Q. Question 30
Refer to Q.29. the probability that bulbs selected randomly from the lot have life less than 900 h, is:

A)

\frac{11}{40}

\frac{5}{16}

\frac{7}{16}

\frac{9}{16}

Q. Fill In The Blanks

In Q.No. 5, the probability that a bulb selected at random from the the lot has life less than 900 hours is _________.

80 bulbs are selected at random from a lot and their life time ( in hours) is recorded in the form of a frequency table given below:

$\begin{matrix} L i f e t i m e (i n h o u r s) & 300 & 500 & 700 & 900 & 1100 F r e q u e n c y & 10 & 12 & 23 & 25 & 10 \end{matrix}$

One bulb is selected at random from the lot. The probability that its life is 1150 h, is:

A) $\frac{1}{80}$
B) $\frac{7}{16}$
C) 0
D) 1

Q. The probability that a bulb selected at random has a minimum battery life of

900

hours

80 bulbs are selected at random from a lot and their lifetime in hours is recorded as under.

$\begin{matrix} Lifetime (in hours) & 300 & 500 & 700 & 900 & 1100 Frequency & 10 & 12 & 23 & 25 & 10 \end{matrix}$

Our bulb is selected at random from the lot. What is the probability that its life is 1150 hours?

(a) $\frac{1}{80}$

(b) $\frac{7}{16}$

(d) 0

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The probability that bulbs selected randomly from the lot has life less than 900 hours is :

The correct option is D 916totalfavourablecases=10+12+23=45∴P(event)=4580=916

The correct option is D $\frac{9}{16}$
$t o t a l f a v o u r a b l e c a s e s = 10 + 12 + 23 = 45 ∴ P (e v e n t) = \frac{45}{80} = \frac{9}{16}$