The probability that two friends share the same birth-month is:

\frac{1}{6}

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\frac{1}{12}

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\frac{1}{144}

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\frac{1}{24}

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Solution

The correct option is B $\frac{1}{12}$
Two friends can share the same birth-month in 12 ways i.e. {January, February.......Dec}
So, favourable ways = 12
and total ways of falling birthdays = 12 × 12

So, required probability $= \frac{12}{12 \times 12} = \frac{1}{12}$

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The probability that two friends share the same birth-month is:

The correct option is B 112Two friends can share the same birth-month in 12 ways i.e. {January, February.......Dec} So, favourable ways = 12 and total ways of falling birthdays = 12 × 12 So, required probability =1212×12=112

The correct option is B $\frac{1}{12}$
Two friends can share the same birth-month in 12 ways i.e. {January, February.......Dec}
So, favourable ways = 12
and total ways of falling birthdays = 12 × 12

So, required probability $= \frac{12}{12 \times 12} = \frac{1}{12}$