The product formed in the given reaction is:

C | O H H_{2} - C | C O O C H_{3} H_{2}

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C | O H_{3} H_{2} - C | C O O H H_{2}

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both A and B are correct

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none of these

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Solution

The correct option is A $C | O H H_{2} - C | C O O C H_{3} H_{2}$
Esters on reaction with alcohols gives derivatives products the mechanism of the reaction is given above.

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Similar questions

C H_{3} C H_{2} C O N H_{2} A \to C H_{3} - C H_{2} - N H_{2} B \to C H_{3} - C H_{2} - O H

A

B

C_{6} H_{5} - C O - {C H}_{2} - {C H}_{2} - C O O H - --- \to N a {B H}_{4}

C H_{3} - C H_{2} - C H_{2} - C O O H + N a O H △ - - \to C a O A + B

C H_{2} = C H_{2} H C l \to C H_{3} - C H_{2} . C l

n C H_{2} = C H_{2} \to (C H_{2} - C H_{3})_{n}

C H_{3} - C O O H + C H_{3} - C H_{2} - O H \to C H_{3} - C O O C H_{2} C H_{3} + H_{2} O

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