Question

The product formed when ethene gas reacts with water in the presence of sulphuric acid is……………………………(ethanol/ethanal/ethanoic acid)

Answer 1

• When Ethene gas(${\mathrm{CH}}_2={\mathrm{CH}}_2$) reacts with Water$\left({\mathrm{H}}_2\mathrm{O}\right)$ in the presence of Sulphuric acid (${\mathrm{H}}_2{\mathrm{SO}}_4$), it undergoes hydration to form Ethyl alcohol$\left({\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{OH}\right)$.
• The chemical reaction is as follows:

$\underset{\mathrm{Ethene}}{{\mathrm{CH}}_2={\mathrm{CH}}_2\left(\mathrm{l}\right)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}\stackrel{{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }\underset{\mathrm{Ethanol}}{{\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{OH}\left(\mathrm{aq}\right)}$

Therefore, the product formed when Ethene gas reacts with Water in the presence of Sulphuric acid is Ethanol $\left({\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{OH}\right)$.