Question

The product obtained from the electrolytic oxidation of acidified sulphate solution , is

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> (JEE MAIN 2021)

• A. $HS{O}_4^{-}$
• B. $H{O}_{2}SOS{O}_{2}H$
• C. $H{O}_{3}SOS{O}_{3}H$
• D. $H{O}_{3}SOOS{O}_{3}H$

Answer 1

The correct option is D $H{O}_{3}SOOS{O}_{3}H$

Anode:

$2H_{2}S{O}_4\to H_2{S}_2{O}_8+2H^{+}+2e^{-}$

$2H_{2}O\to O_2+4H^{+}+4e^{-}$

Cathode :

$e^{-}+H^{+}\to \frac{1}{2}{H}_2$

Main product of electrolysis of conc. $H_{2}S{O}_4$ is
$H{O}_{3}SOOS{O}_{3}H\text{or}\left(H_2{S}_2{O}_8\right)$