Question

The product of $4a^2$, $-6b^2$ and $3a^2{b}^2$ is

• A. $a^2{b}^2$
• B. $13a^4{b}^4$
• C. $-72a^4{b}^4$
• D. $a^4{b}^4$

Answer 1

Answer: (C)

$-72a^4{b}^4$

$4a^2\times (-6b^2)\times 3a^2{b}^2$

$=4\times a\times a\times -6\times b\times b\times 3\times a\times a\times b\times b$

$=4\times -6\times 3\times a\times a\times a\times a\times b\times b\times b\times b$

$=-72a^4{b}^4$