The product of reaction between one mole of acetylene and two mole of HCHO in the presence of $C u_{2} C l_{2}$ -

H O C H_{2} - C \equiv C - C H_{2} O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} C = C H - C \equiv C - C H_{2} O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C \equiv C - C H_{2} O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $H O C H_{2} - C \equiv C - C H_{2} O H$
Acetylene when reacts with two moles of formaldehyde in presence of copper as a catalyst then ethynyl diol is formed. In this reaction, the copper group targets the acidic C attached to the triple bond.

Suggest Corrections

Similar questions

H O C H_{2} - C H_{2} O H

C H_{2} O H

|

C H_{2} - C - C H_{2} O H

|

C H_{2} O H

I U P A C

{C H}_{3} - C | B r = C H - C H_{2} O H

{C H}_{3} - C H_{2} - C H = C H - \circ ∥ C - H O H

C H_{3} - C H_{3} | C H - O | | C - C H_{2} - C H_{2} O H

C H_{2} = C H - C H O \to C H_{2} = C H - C H_{2} O H

Join BYJU'S Learning Program