The product of zeroes of a cubic polynomial $x^{3} - 3 x^{2} - x + 5$ is

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-5

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-1

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Solution

The correct option is B -5
If $α$ , $β$ and $γ$ are the the zeroes of a cubic polynomial $a x^{3} + b x^{2} + c x + d$ ,
then
$α$ $β$ $γ$ $= \frac{- d}{a}$
Given polynomial: $x^{3} - 3 x^{2} - x + 5$
$∴$ Product of zeroes is $\frac{- 5}{1}$ = -5.

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