Question

The product(s) when dichlorine hexoxide reacts with $NaOH$ is(are):

• A. $NaCl{O}_4$
• B. $NaOCl$
• C. $NaCl{O}_2$
• D. $NaCl{O}_3$

Answer 1

Answer: (A), (D)

The correct options are
A

$NaCl{O}_4$

D

$NaCl{O}_3$

In the gaseous state, the formula $C{l}_2{O}_6$ is accurate but in the liquid (red) and solid states, the compound exists as chloryl chlorate - $\left[Cl{O}_2^{+}\right]\left[Cl{O}_4^{-}\right]$. strangely, it is not a dimer of the other chlorine oxide - $Cl{O}_3$. At room temperature, it is a dark red fuming liquid that crystallizes into a red ionic solid.

$C{l}_2{O}_6+2NaOH⟶NaCl{O}_4+NaCl{O}_3+H_{2}O$