The products for the following reaction will be:

$3 C_{2} H_{5} O H + P C l_{3} Pyridine - ---- \to Products$

3 C H_{3} O H + P C l

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3 C_{2} H_{5} C l + H_{3} P O_{3}

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C_{6} H_{14} + H_{3} P O_{3}

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None of the above

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Solution

The correct option is B $3 C_{2} H_{5} C l + H_{3} P O_{3}$
Reaction of Alcohol with $P C l_{3}$ :
$3 R - O H + P X_{3} Pyridine - ---- \to 3 R - X + H_{3} P O_{3}$
Here,
$X = C l, B r$
Steps Involved in the Mechanism
Protonation of the alcohol
Attack of the nucleophile
$C l^{-} + C H_{3} - C H_{2} - O P C l_{2} \to C H_{3} C H_{2} C l +^{-} O P C l_{2}$
The same mechanism will be followed by the rest 2 molecules of alcohol.
So,
$3 C_{2} H_{5} O H + P C l_{3} Pyridine - ---- \to 3 C_{2} H_{5} C l + H_{3} P O_{3}$

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