The products formed when an aqueous solution of $N a B r$ is electrolysed in a cell having inert electrodes are :

N a

and

B r_{2}

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N a

and

O_{2}

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H_{2}, B r_{2}

and

N a O H

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H_{2}

and

O_{2}

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Solution

The correct option is D $H_{2}, B r_{2}$ and $N a O H$
$N a B r ⇌ N a^{+} + B r^{-}$
$2 H_{2} O + 2 e \to H_{2} + 2 O H^{-}$
$N a^{+} + O H^{-} \to N a O H$ At cathode
$B r^{-} \to B r + e^{-}$
$B r + B r \to B r_{2}$ At anode
So the products are $H_{2}$ and $N a O H$ (at cathode) and $B r_{2}$ (at anode).
Hence, option C is correct option.

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N a_{2} S O_{4}

When the aqueous solution of $L i_{2} S O_{4}$ electrolyzed the products formed at cathode and anode respectively are

N a C l

H_{2}

N a

H_{2}

N a_{2} S O_{4}

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