The proposition p - p - p - p is a

The correct option is D contradictionp p P⇒ #160; #160; P P⇒ P (P⇒ P)∧ ( P⇒ P) TF #160;F #160; #160;T #160; #160; #160; #16 ...

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Displacement of COM:Application

The propositi...

Question

The proposition $(p \Rightarrow p) \land (p \Rightarrow p)$ is a

Tautology

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neither tautology nor contradiction

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contradiction

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None of these

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(p \Rightarrow\sim p) \land (\sim p \Rightarrow p)

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p \lor (\sim p \lor q)

The proposition $p \to\sim (p \land \sim q)$

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p	~p	$P \Rightarrow P$	$P \Rightarrow P$	$(P \Rightarrow P) \land (P \Rightarrow P)$
T	F	F	T	F
F	T	T	F	F