The proposition p- p- - p- p is a-

The correct option is B Contradiction #160; p #160; ∼ p #160; p⇒∼ p ∼ p⇒ p (p⇒∼ p)∧ (∼ p⇒ p) #160; #160; #160; T #1 ...

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Mathematical Statement

The propositi...

Question

The proposition $(p \Rightarrow\sim p) \land (\sim p \Rightarrow p)$ is a.

Tautology and contradiction

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Neither tautology nor contradiction

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Contradiction

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Tautology

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Solution

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Similar questions

(p \Rightarrow\sim p) \land (\sim p \Rightarrow p)

(p \Rightarrow\sim p) \land (\sim p \Rightarrow p)

(p \Rightarrow\sim p) \land (\sim p \Rightarrow p)

p \lor (\sim p \lor q)

The proposition $p \to\sim (p \land \sim q)$

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$p$	$\sim p$	$p \Rightarrow\sim p$	$\sim p \Rightarrow p$	$(p \Rightarrow\sim p) \land (\sim p \Rightarrow p)$
$T$	$F$	$F$	$T$	$F$
$T$	$F$	$F$	$T$	$F$
$F$	$T$	$T$	$F$	$F$
$F$	$T$	$T$	$F$	$F$