Question

The Pythagorean triplet whose one of the member is 16 is

• A. 16, 43, 45
• B. 16, 63, 65
• C. 16, 40, 44
• D. 16, 60, 64

Answer 1

The correct option is B

16, 63, 65

If we take m² + 1 = 16, then m² = 15
The value of m will not be an integer.

If we take m² − 1= 16, then m² = 17
Again, the value of m is not an integer.

So, let 2m = 16
m = 8
Thus, m² − 1 = 64 − 1 = 63 and m² + 1 = 64 + 1 = 65
Therefore, the required Pythagorean triplet is 16, 63, and 65.